[sac-user] Fwd: [sac-devel] Cartesian products in SAC

Sven-Bodo Scholz S.Scholz at herts.ac.uk
Fri Dec 2 18:12:51 CET 2005


I think this email belongs into sac-user 
rather than sac-devel....

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Date: Thu, 1 Dec 2005 18:30:00 -0500 (EST)
From: Robert Bernecky <bernecky at rogers.com>
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Subject: [sac-devel] Cartesian products in SAC
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I have an interesting problem, and am looking for
spiffy ideas on how to solve it:

The problem is that of "dyadic transpose" in APL,
which does more than it really should:

 - It provides a way to permute array axes, as
   a general transpose. For example,
   the transpose([2,0,1,3], genarray([2,3,4,5],6))
   produces a result of shape [3,4,2,5].
   
 - It provides a general "main diagonal" capability
   if you include duplicates in the left argument.
   For example transpose([0,0], rank2matrix) gives
   the main diagonal vector. On the above example,
   the result of a [2 0 0 1] transpose would be an
   array of shape [3,5,2]: axes 1 and 2 would
   be collapsed into a single axis.

A bit of analyzis on the left argument value and
right argument shape yields two vectors:

   - result shape
   - index steps.

Successive pairs of elements form a nest of FOR
loops, e.g:

    result shape: [3,4,2.5]
    steps: [20, 5, 60, 1]

The actual work can be viewed as a nest of FOR loops:
   for i    in 20*iota 3
    for j   in 5 *iota 4
     for k  in 60*iota 2
      for L in  1*iota 5
       z[...] = ravel(rightargument)[i+j+k+L];
   endfors

It can also be viewed as a Cartesian product:

  (20*iota 3)outerproduct+ (5*iota 4) outerproduct+
  (60*iota 2)outerproduct+ (1*iota 5)

where outerproduct+(x,y) is an array of
shape ((shape(x)++shape(y)), composed of
    x[scalar]+y

How do I express this nicely in SAC?
And, how do I express it nicely in SAC when I don't know
the shape of the above result shape and index steps
vectors until run-time?

I can flatten the nested loops into a nasty sort of single loop, with
end-of-innermore loop index corrections, but I'd rather not, if
someone has a nicer way to do it.

Bob
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